90 lines
2.5 KiB
Python
90 lines
2.5 KiB
Python
# -*- coding: utf-8 -*-
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"""人民币金额转中文大写。"""
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def amount_to_cn(amount):
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"""1234.56 -> 壹仟贰佰叁拾肆元伍角陆分"""
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digits = u"零壹贰叁肆伍陆柒捌玖"
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units = [u"", u"拾", u"佰", u"仟"]
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big_units = [u"", u"万", u"亿", u"兆"]
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try:
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amount = round(float(amount) + 0.0, 2)
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except (TypeError, ValueError):
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return u"零元整"
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negative = amount < 0
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amount = abs(amount)
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integer_part = int(amount)
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# 避免浮点误差：分位用字符串处理
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fen = int(round((amount - integer_part) * 100))
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if fen == 100:
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integer_part += 1
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fen = 0
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def int_section(num):
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"""0-9999 转中文"""
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s = u""
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zero_flag = False
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str_num = "%04d" % num
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for i, ch in enumerate(str_num):
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d = int(ch)
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pos = 3 - i
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if d == 0:
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zero_flag = True
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else:
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if zero_flag and s:
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s += digits[0]
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zero_flag = False
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s += digits[d] + units[pos]
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return s
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if integer_part == 0:
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result = u""
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else:
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sections = []
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n = integer_part
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while n > 0:
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sections.append(n % 10000)
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n //= 10000
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parts = []
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for idx, sec in enumerate(sections):
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if sec == 0:
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parts.append(u"")
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continue
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parts.append(int_section(sec) + big_units[idx])
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result = u""
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for idx in range(len(parts) - 1, -1, -1):
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p = parts[idx]
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if not p:
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if result and not result.endswith(digits[0]):
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result += digits[0]
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continue
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if result and idx < len(parts) - 1 and sections[idx] < 1000:
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result += digits[0]
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result += p
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result = result.rstrip(digits[0]) or u"零"
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if fen == 0:
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result += u"元整" if result else u"零元整"
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else:
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jiao = fen // 10
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f = fen % 10
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if result:
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result += u"元"
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if jiao:
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result += digits[jiao] + u"角"
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elif f and result:
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result += digits[0]
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if f:
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result += digits[f] + u"分"
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if negative:
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result = u"负" + result
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return result
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if __name__ == "__main__":
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for v in (0, 0.05, 0.5, 1, 10, 100.5, 1234.56, 10000, 1002003, 20340.07,
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100000000, 10500.5):
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print(v, amount_to_cn(v))
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